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FEELIP
08-04-2007, 09:51 AM
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I dropped a ball from 3ft,6ft, and 12ft. For each of those positions i have to use the position function to calculate the times. My original times were .56,.61,.87. The books position function is s(t)=-16t(squared)+initial velocity(in ft)+original height. I also have to verify this algebraically. Can someone please help me?

Mr. Hui
08-04-2007, 12:35 PM
I don't understand the problem.

s(t)=-16{t^2}+Initial Velocity+Initial Height

What time are you calculating for? the time it takes to hit the ground?

FEELIP
08-04-2007, 12:47 PM
neither do i..lol ;-)... that is the formula my book has " the position function for a free falling object near earth's surface" unless there is a different position function that i am supposed to be using

FEELIP
08-04-2007, 12:48 PM
I don't understand the problem.

s(t)=-16{t^2}+Initial Velocity+Initial Height

What time are you calculating for? the time it takes to hit the ground?

yes the time it take to hit the ground

Mr. Hui
08-04-2007, 03:38 PM
When you drop a book at 12 feet, the initial velocity is 0. So the position function is:

s(t)=-16{t^2}+12=0
16{t^2}=12
t^2=0.75
t=\sqrt[2]0.75
t\approx0.87

Conclusion: Your answer is correct.

FEELIP
08-06-2007, 11:04 AM
Thank, now I see what I was doing wrong. Thank you so much.