XP Math - Forums - View Single Post - Algebra question?
 Thread: Algebra question? View Single Post
 07-28-2007 #3 Jayclassof1 Guest   Posts: n/a 1 Nickel = \$ 0.05 1 Dime = \$ 0.10 1 Quarter = \$ 0.25Let x be the number of nickels. The question says that the number of dime is equal to twice as nickels.So, the number of dimes = 2 xAlso, given that the number quarter is five more than dimesSo, number of quarter = 2 x + 5Totally Jamie's bank have \$6.50 of combination of all nickel , dime and quarters,Therefore, the expression becomes,(no. of nickels ) * (0.05 ) + (no.of dimes)*(0.10) +(no. of quarters) * (0.25) = \$ 6.50That is, x * 0.05 + 2x * 0.10 + (2x+5) * 0.25 = 6.50 0.05x + 0.2 x + 0.5 x + 1.25 = 6.50 0.75 x + 1.25 = 6.50Subtract both sides by 1.25 0.75x + 1.25 - 1.25 = 6.50 - 1.25 0.75 x = 6.50 - 1.25 = 5.25Now, divide both sides by 0.75Implies that, 0.75 x = 5 . 25 ------------------------- 0.75 0. 75 x = 7So, Number of nickels = 7Number of dimes = 2x = 2 * 7 = 14Number of quarters = 2x + 5 = 14 + 5 = 19Hence, Nickel = 7 , Dime = 14 , Quarter = 19.=============================================== For more assistance please visit www.classof1.com.Classof1 - leading web tutoring and homework help.Toll free - 1877-252-7763