Quantcast XP Math - Forums - View Single Post - can someone answer these problems about probability and statistics?
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Old 07-28-2007   #4
Amber E
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This is basically the counting principle--you just multiply the individual probabilities to find the total. #1: 3 x 4 x 3 = 36 possibilities#2: there are three ways of getting each question wrong, so 3x3x3x3x3 is 243#3: (a) there are seven possibilities for the first number (0 1 2 3 4 5 or 6), 6 possibilities for the second number (take off whatever was used for the first) and 5 for the third number. So 7x6x5 is 210(b) Same process, but the last number has to be odd. so the last number is 3 instead of 5 7x6x3 so 126(c) same process, but hte first two have to be bigger than three. So the first one can be a 4 a 5 or a 6, same with the second. Except the second can't match, so there are only two possibilities. The last number can't be 0, so there are six possibilities3x2x6=364. Need more details. In that order, or just those 4 cards? 5. If you don't have to account for the actual color, just how many orders of bulbs, it is 11!Otherwise, you would have to do permutations and I'd use a calculator (which I don't have here)