Explain the calculation for new this simple probability problem (ANSWER GIVEN)?
Two heterozygous parents for albinism. If they have four children, what is the probability of them having 3 normal children and one albino?For people without biological knowledge, the probability of having a normal child will be 3/4, the probability of having an albino child is 1/4. The answer to this question is 27/64, which happens to be (3/4)^3, or also (3/4)^3(1/4) x 4C3, but honestly i have no idea what is the correct way to think about or get to the answer, i just had the answer and noticed those two ways to get to it. please explain work, thank you
