Ok I worked at the first problem and figured it out.
using the identity 1/sinx = cscx...
(2/(sinx)^2)x = 2(csc^2)x
Using the identity cosx/sinx = cotx
3cosx/((sinx)^2) = 3cotx/sinx
And using the identity 1/sinx = cscx
3cotx/sinx = 3cscxcotx
Giving a final developed equation of
(integral) (2(csc^2)x + 3cscxcotx + sinx) dx
Remembering these derivatives
cosx = -sinx
cscx = -cscxcotx
tanx = (csc^2)x
Final integrated answer = -2cotx - 3cscx - cosx + C
C being any integer.
But I still can't figure out the second one, although it's probably much easier
