2x^34x^23x6Use the grouping method since there are 4 terms(2x^34x^2)+(3x6)Now factor out like terms in each group2x^2(x+2)3(x+2)Since the terms inside the ( ) are equal, that is a factorTake the numbers outside the ( ) and that is another term(2x^23)(x+2)You can also take the negative out of the first term to get(2x^2+3)(x+2)The first term does not factor any more, so your answer is:(2x^2+3)(x+2)
