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Old 03-30-2007   #8

Join Date: Nov 2006
Posts: 446

Originally Posted by zwu_ca View Post
Suppose one side of the rect is x, the other side is (160-2x)/2=80-x (taking account of 10 feet of the door).. The area is x(80-x) = 80x - x^2 = 1600 - (1600-80x+x^2) = 1600 - (x-40)^2. So maximum area is reached when x is 40. The dim is 40x40.

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