Quote:
Originally Posted by zwu_ca
Suppose one side of the rect is x, the other side is (1602x)/2=80x (taking account of 10 feet of the door).. The area is x(80x) = 80x  x^2 = 1600  (160080x+x^2) = 1600  (x40)^2. So maximum area is reached when x is 40. The dim is 40x40.
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