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07-25-2007

Assume we are solving for x.x^2+a(a-2x)=a^2+x(x-2a)x^2 + a^2 - 2ax = a^2 + x^2 - 2ax0 = 0The original equation is an identity. An identity is an equation that is true for all real numbers x.Answer: x is any real number.

07-25-2007	#2
mathjoe Guest Posts: n/a	Assume we are solving for x.x^2+a(a-2x)=a^2+x(x-2a)x^2 + a^2 - 2ax = a^2 + x^2 - 2ax0 = 0The original equation is an identity. An identity is an equation that is true for all real numbers x.Answer: x is any real number.