u differentiate...usin product rule....u'v+ uv' where u is the first term (e^x) and v is the second ln (x)so the differential of e^x is e^x and the differential of ln x is 1/x(if u wondering how? its bcoz the mathmatician whoever made this said so)so usin product rule: e^x*ln (x) + e^x*1/x
