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Old 06-15-2007   #4
YvesBenoit
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Sorry, yes the 2nd was an equation. I played around with it and seem to have figured it out as well.

f(x) = (1/4)^x * 16^(x/2)

(1^x / 4^x) * 16^(x/2)

1^x = 1 so

f(x) = 1/(4^x) * 16^(x/2)
= 16^(x/2) / (4^x)
= (sqrt16)^x / (4^x)
= 4^x / 4^x
= 1

I know I know... ended up figuring it by myself. However I did end up wasting hours while trying to figure it out.