Quote:
Originally Posted by dockyard
The figure shows a conical water carrier. it is filled to 25%.
How high does the water reach?
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The formula for the volume of a cone is:
V = (1/3)*pi*(r^2)*h
So the volume of the entire water carrier is:
V = (1/3)*pi*(16^2)*96 = 25,735.927 cm^3
If the carrier is only filled up to one-fourth of its volume then:
(1/4)*25,735.927 = 6433.982 cm^3
Then to solve for the height:
6433.982 = (1/3)*pi*(16^2)*h
h = 24 cm. So the water reaches up 24 cm in the carrier, or one-fourth the height of the carrier.