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Old 07-04-2009   #2

Join Date: Dec 2008
Posts: 249

Originally Posted by dockyard View Post
The figure shows a conical water carrier. it is filled to 25%.
How high does the water reach?

The formula for the volume of a cone is:
V = (1/3)*pi*(r^2)*h

So the volume of the entire water carrier is:

V = (1/3)*pi*(16^2)*96 = 25,735.927 cm^3

If the carrier is only filled up to one-fourth of its volume then:

(1/4)*25,735.927 = 6433.982 cm^3

Then to solve for the height:

6433.982 = (1/3)*pi*(16^2)*h

h = 24 cm. So the water reaches up 24 cm in the carrier, or one-fourth the height of the carrier.
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