Quantcast XP Math - Forums - View Single Post - Inequality problem help!
View Single Post
Old 05-13-2010   #2

Join Date: Dec 2008
Posts: 249

Originally Posted by sashi View Post
can someone help me and explain how to solve this? i hope somene can solve this and help me XD


Uploaded with ImageShack.us
Look at the left hand side (LHS) of the inequality. For what values of x does the LHS become less than 0? 1 -sqrt(3) is approx. -0.73205.

x - 0.73205 <= 0
x <= 0.73205

So for those values of x, is the right hand side (RHS) ever less than 0?

10(0.73205)^2 + 7 = 12.359
As x gets smaller than 0.73205, the RHS is never less than zero. So all values of x <= 0.73205 satisfy the inequality.

Now we need to check values of x greater than 0.73205

The LHS is the graph of a line, while the RHS is a parabola opening upward with a vertex at (0,7). So for values of x >0.73205 the parabola will always be greater than the line since it increases at a faster rate than the line.

Therefore, all real values of x will satisfy the inequality. If x can be a complex number, then the solution is more difficult.
MAS1 is offline   Reply With Quote