XP Math - Forums - View Single Post - Integration... I need answers quick
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 09-05-2007 #5 Temperal Guest   Posts: n/a I'll try one of the easy ones for warmup; I'll do the rest, if I can, later. 8) This is quite easy. You just break it into sections, and use the product rule. $\int sec^2(\theta)tan^2(\theta) d(\theta)$ So, first work with $\int\sec^2{\theta}$ Is equal to $\int \ln{|sec{\theta}+\tan{\theta}|}^2 \text{ d}(\theta)$ as every good calc student knows. (Well, plus a constant, but we'll just stick that in at the end) now, $\int\tan^2{\theta}\text{ d}(\theta)$ is equal to $-\ln{|cos x|}^2$ Now apply the product rule $\int f(x)\cdot g(x)=(\int f(x))g(x)+f(x)(\int g(x))$ I'll leave you to solve. Last edited by Temperal; 09-05-2007 at 08:33 PM..