1. take the dirivative of the function using the quotient rule dy/dx= 2x/x^42. use the x point and plug it into the dy/dx equation to find the slope at that point dy/dx= 2(1)/1^4= 23. then you have that equation of a line, y=mx+b and you can plug in what you know to solve for b 1= 2(1)+b b=3 (the x and y value come from the point given in the problem and the m value is the derivative evaluated at that point)4. so the equation on the tangent line is y= 2x+3
