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Old 07-24-2008   #1
rousse101
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Default Calculus

The area of the region:y = x^1/2 and y=-x+6
enclosed by the two graphs and the x-axis is given by:
2
∫− x +6 − x^1/2 dx .....a)
0
2
∫− x +6 − x^1/2 dx .....b)
-3
2
∫ 6− y − y^2 dy ....c)
0
2
∫y2- (6-y) dy .....d)
-3