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Old 07-30-2007   #4
Imherenowwhat
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1. take the dirivative of the function using the quotient rule dy/dx= -2x/x^42. use the x point and plug it into the dy/dx equation to find the slope at that point dy/dx= -2(1)/1^4= -23. then you have that equation of a line, y=mx+b and you can plug in what you know to solve for b 1= -2(1)+b b=3 (the x and y value come from the point given in the problem and the m value is the derivative evaluated at that point)4. so the equation on the tangent line is y= -2x+3
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