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Old 07-30-2007   #5
sonny torreli
Posts: n/a

derivative of the given function dy/dx= -2/x^3 (nx^[n-1])so the slope's = -2/x^3when x=1 (from point 1,1)slope = -2/1 = -2so the equation of a line as we know y=mx+cwhen passing thru one pointy-y1=m(x-x1)y1=1;x1=1 (from the point given)slope m we have found out = -2so the equation of the line : y-1= -2(x-1) => y-1= -2x+2 =>y+2x= 2 (bringing x to left,and -2 to right)or 2x+y = 2hope its fully clear now
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