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Old 04-25-2009   #1
bhagyashree95
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Red face Algebra help needed

I was trying to get the a variables on one side of the equation and the b variables on the other side of the equation but I couldn't. Can anyone else separate these two variables?

( P.S. The equation is in the attached document.)

Thanks for helping!!!
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File Type: doc The Golden ratio formula.doc (23.5 KB, 98 views)
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Old 04-26-2009   #2
MAS1

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Quote:
Originally Posted by bhagyashree95 View Post
I was trying to get the a variables on one side of the equation and the b variables on the other side of the equation but I couldn't. Can anyone else separate these two variables?

( P.S. The equation is in the attached document.)

Thanks for helping!!!
If you are trying to solve for phi then:

(a + b)/(a) = a/b = phi where a > b, and b not equal to 0

Since a/b = phi, cross multiply to get a = b*phi

Substitute b*phi for a giving;

(b*phi + b)/(b*phi) = (b*phi)/b

Cross multiply to get;

(b^2)*phi^2 = (b^2)*phi + b^2

(b^2)*phi^2 = (b^2)(phi + 1)

phi^2 = phi + 1
phi^2 - phi - 1 = 0

Solve for phi. phi = (1 + sqrt(5))/2 (Ignore the (1 - sqrt(5))/2 case).
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Old 05-18-2009   #3
cambernae
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Quote:
Originally Posted by bhagyashree95 View Post
I was trying to get the a variables on one side of the equation and the b variables on the other side of the equation but I couldn't. Can anyone else separate these two variables?

( P.S. The equation is in the attached document.)

Thanks for helping!!!
i really dnt know but if u have someproblem just ask someone u know because i reallly dnt get this situation
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