math problem? - XP Math - Forums

 XP Math - Forums math problem?

 07-30-2007 #1 s4apple Guest   Posts: n/a math problem? A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down the middle parallel to one side. What is the shortest length of fence that the rancher can use?
 07-30-2007 #2 EMERGENCY Guest   Posts: n/a YOU GOTTA DO CALCULUS TEEE HEEEE. I could do this but if you look in your book theres an example exactly like this.
 07-30-2007 #3 Popo B Guest   Posts: n/a I think the shortest possible length will be achieved if the field is a square(which is also a rectangle). So, the length of one side would be: âˆš1500000 = 1224.74Therefore, the length of fencing required would be:1224.74*5 [4 sides + the one in the middle]=30618.62 ft//
 07-30-2007 #4 Engineer-Poet Guest   Posts: n/a 6000 feet of fence.Let L be the length of fence, W the width of the area, D is the depth. The width is divided in half by the middle part of the fence.W = 1,500,000 / DL = 2 W + 3 D = 3,000,000 / D + 3 DdL = 3 - 3,000,000 / D^2 The length of fence is at a minimum when dL = 0. 3 - 3,000,000 / D^2 = 0Â* Â* Â* Solve for D3 D^2 = 3,000,000D = 1000W = 1500, L = 2W + 3D = 6000

 Thread Tools Display Modes Linear Mode

 Posting Rules You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Forum Rules
 Forum Jump User Control Panel Private Messages Subscriptions Who's Online Search Forums Forums Home Welcome     XP Math News     Off-Topic Discussion Mathematics     XP Math Games Worksheets     Homework Help     Problems Library     Math Challenges

All times are GMT -4. The time now is 02:28 AM.

 Contact Us - XP Math - Forums - Archive - Privacy Statement - Top