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12052006  #1 
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Algebra based question
Hi everyone, I am new to this site. I was wondering if anyone here can help me answer a question, in order for me to study correctly for my math test tomorrow.
Here's the question: Melissa plans to put a fence around her rectangular garden. She has 150 feet of fencing material to make the fence. If there is to be a 10 foot opening left for an entrance on one side of the garden, what dimensions should the garden be for maximum area? This question has to be answered in vertex form. If anyone can answer this and explain it step by step to me that would be great! 
12062006  #2 
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Solution:
Suppose one side of the rect is x, the other side is (1602x)/2=80x (taking account of 10 feet of the door).. The area is x(80x) = 80x  x^2 = 1600  (160080x+x^2) = 1600  (x40)^2. So maximum area is reached when x is 40. The dim is 40x40.
http://www.mathpotd.org 
12062006  #3 
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So that would be how u do it in vertex form?
what does ^ this mean? Thanks 
12062006  #4 
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x^2 = x.x, i.e., x times x.
The vertex form can be many, many. Here is a one:
(0,0), (0,10), (0,40), (40,40), (40,0). Last edited by zwu_ca; 12062006 at 06:51 PM.. 
12062006  #5 
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wait i think i do....so the answer is 40 by 40 or do i have 2 do another step?

12072006  #6 
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We don't know what exactly the original problem is.
If the original problem required the vertex form, we have to do another step.
Math Problem of the Day 
12082006  #7 
Join Date: Nov 2006
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what is vertex? u mean angles blah i dony know
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03302007  #8  
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