Calculus...? - XP Math - Forums

 XP Math - Forums Calculus...?

 08-06-2007 #1 me y Guest   Posts: n/a Calculus...? f(x) = 0 if x < -3 5 if -3 < (or equal) x < 0 -3 if 0 < (or equal) x < 4 0 if x >(or equal) 4g(x) = âˆ« (low: -3, up: x) f(t) dtDetermine the value of each of the following:g(-7) = ______g(-2) = ______g(1) = ______g(5) = ______The absolute maximum of g(x) occurs when x = ______ and is the value _______.
 08-06-2007 #2 laid_back_dude 23 Guest   Posts: n/a I am extremely sorry, it was late. made a terrible mistake.when u integrate x, it yields (x^2)/2;-7 < -3 ; x= 0g(-7)= (1/2) * [ 0^2 -(-3)^2] = - 9/2-2>-3; x=5g(-2) = (1/2) * [ 5^2 -(-3)^2] = 1/2* (15-9) = 6/2 = 3-3
 08-06-2007 #3 Portrait of Circles Guest   Posts: n/a whats z

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