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Old 07-30-2007   #1
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Default algebra help?

Find the inverse of f(X)1.) f(X) = 5X + 42.) f(X) = X^2 + 33.) f(X) = -5X+ 2 4.) f(X) = 3X-1 -- ------ 4on the last question, the ( ------- 4) goes under 3X - 1.
Old 07-30-2007   #2
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1. y= 5x +4 y - 4 = 5x y-4 /5 = x x - 4 /5 = y = f(x)2. y = x^2 + 3 y - 3 = x^2 extract the root from y - 3 = x root x-3 = y = f(x)The other are easy when you know understand the way to solve.
Old 07-30-2007   #3
Another lazy kid
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Do you mean additive inverse or multiplicitive inverse? I'm not sure right now, but wouldn't the multiplicitive inverse be the denominator (bottom number)over the numerator (top number)? If so, wouldnt the invrse of f(x) simply be f(x)=1/[f(x)] ( in the case of the last one, note that 1/[f(x)] would equal 4/(3x-1))?I am not a mathemetician, nor do i like Algebra, but I think your question was a bit vauge. Sorry I couldn't help much.

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