Algebra Problem? - XP Math - Forums

 XP Math - Forums Algebra Problem?

 07-26-2007 #1 mesrobyet Guest   Posts: n/a Algebra Problem? (2x^2+5x-3)(4x-1)=ax^2+bx^2+cx+dWhat is the value of b?Please also state how you solved it.SORRY, TYPO! IGNORE ABOVE EQUATION!(2x^2+5x-3)(4x-1)=ax^3+bx^2+cx+d ^ Third, not second.
 07-26-2007 #2 Paris Guest   Posts: n/a Assuming you could do it without the exponents...you have to match them up according to that exponent.5^0 is different than 5^1
 07-26-2007 #3 diburning Guest   Posts: n/a It's hard to explain, but here's the answer8x^3)+(18x^2)-12x+3Since the form is (Ax^3)+(Bx^2)+Cx+DB = 18x^2
 07-26-2007 #4 ttly^tink Guest   Posts: n/a sorry i couldnt shorten it further but i shortened the problem to 8x^3+18x^2-17x+3=Ax^3+Bx^2=Cxwe never did that in my algebra class this year 0.0 but i did the most i cud srrrrrrry
 07-26-2007 #5 Kevin B Guest   Posts: n/a You could go through the trouble of multiplying out your terms, or just isolate on what will give you x^2 terms - in this case, 4x * 5x, and 2x^2 * (-1), which gives you 20x^2-2x^2, or 18x^2. Therefore, b = 18.

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