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Old 07-20-2007   #1
missy prapjel
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Default (x-4)(x-1),multiplying algebra expressions?

pls i want someone who understands this concept very well to answer.
 
Old 07-20-2007   #2
YvesBenoit
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(x-4)(x-1)

Alright, there are 3 steps. Each of these steps will determine a "part" of the answer.

First, take the first term, in this case, x.

x

Second, total up your integers. In this case, -4 + -1 = -5.

Third, multiply both integers. -4 * -1 = 4.

This gives x, -5, 4.

Each part must be raised to the power of 2, 1, 0, respectively.

Final answer (x^2) -5x + 4
 
Old 02-21-2010   #3
jmw106462

 
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x^2-5x+4 is the answer
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Old 08-20-2013   #4
Dark88Dragon
 
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(x-4)*(x-1) = ((x*x) + x*(-1)) (+) ((-4)*x (+) (-4*(-1)) = x*x-x-4x+4 =
x² - 5x + 4; for example: x = 10 ---> 10² - 5*10 + 4 = 100 - 50 + 4 = 54;

I hope that was not too complicated
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Old 11-29-2013   #5
Jonathan W

 
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Quote:
Originally Posted by missy prapjel View Post
pls i want someone who understands this concept very well to answer.
I know this thread is dead, but since someone revived it, I might as well answer it.

I think you can factor this by using the Distributive Property. So, (x - 4)(x - 1) would become x(-4 - 1)
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