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#1 |
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![]() Point C is the midpoint of , D is the midpoint of , E is the midpoint of and F is the midpoint of . On a piece of paper, draw a diagram that represents this situation. If CF=x, find the length of the following in terms of x: a. DA b. FBlet me rephrase tht Point C is the midpoint of line AB, D is the midpoint of line AC , E is the midpoint of line CB and F is the midpoint of line DB . On a piece of paper, draw a diagram that represents this situation. If CF=x, find the length of the following in terms of x: a. DA b. FB
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#2 |
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![]() 2X and 3X
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#3 |
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![]() well like you said draw a diagram and figure it out ur self. you have the info.
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#4 |
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![]() well 2 of cf is equal to one section NOT including any f.. (the proportioned ones) so da= 2xfb = the other half of the midpoint with f( just x) plus another length equivolent to da (2x) so therefore it is 3xDA=2xFB=3x
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#5 |
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![]() draw a line .......... put A, D, C, E, B IN THIS ORDER , and with equal distance between each two successive points , then put F in the middle between C , E If CF=x , then FE = x & CE = 2x , AD = DC = CE = EB = 2xa. DA = 2xb. FB= 3x
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#6 |
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![]() DA = 2xFB = 3x
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