Math Help! Find four consecutive integers such that the sum of the second and

fourth is 132.? Really need help with this.Thanks in advance!

64, 65, 66, 67

So assign the 4 integers:x, x+1, x+2 and x+3so x+1 and x+3 equal 132x+1 + x+3 = 132 (combine like terms)2x + 4 = 132 (subtract 4 from each side)2x = 128 (divide by the number in front of x)x = 64So the numbers would be 64, 65, 66 and 67

let the smallest of those integers be x.since they are all consecutivethe integers are x, x+1, x+2 , x+3adding second and fourth integer=> (x+1) + (x+3) = 132=> 2*x + 4 = 132=> 2*x = 128=> x = 64therefore the intergers are64,65,66,67