plis help me to answers math question?

dy ~~ e^x ln [x] =............dxthanks before

... derivate.. just do product rule.. e^x[1/x]+[ln(x)*e^x]

u differentiate...usin product rule....u'v+ uv' where u is the first term (e^x) and v is the second ln (x)so the differential of e^x is e^x and the differential of ln x is 1/x(if u wondering how? its bcoz the mathmatician whoever made this said so)so usin product rule: e^x*ln (x) + e^x*1/x