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Old 08-04-2007   #1
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Default algebra help?

factor completely with respect to the integers.-2x^3-4x^2-3x-6
Old 08-04-2007   #2
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-2x^3-4x^2-3x-6you can solve tis by synthetic divisionmultiply by - on both sidetake the coeff of x^3,x^2,x and the constant 6and do synthetic divisionthe answer is (x+2)(2x^2+3)
Old 08-04-2007   #3
Ryan R
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-2x^3-4x^2-3x-6Use the grouping method since there are 4 terms(-2x^3-4x^2)+(-3x-6)Now factor out like terms in each group-2x^2(x+2)-3(x+2)Since the terms inside the ( ) are equal, that is a factorTake the numbers outside the ( ) and that is another term(-2x^2-3)(x+2)You can also take the negative out of the first term to get-(2x^2+3)(x+2)The first term does not factor any more, so your answer is:-(2x^2+3)(x+2)

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