please help me with this math question?

Write an equation of a line that is perpendicular to y = 2x + 3 and passes through (3,4).how do you guys get these answers?...do you solve them by yourselfs or do u use a website?

y - 4 = (-1/2)(x-3), in point-slope form-------------Reason: (-1/2)(2) = -1. If one slope is 2, then the other one must be -1/2 if the two lines are perpendicular to each other.

Y=5x+3?

y = -(1/2)x + 11/2

y = 2x + 3so the slope of this line is m = 2the slope of line perpendicular this line is m = -1/2if it passes through (3,4) therefore(y - y1) = m (x - x1)(y - 4) = -(1/2)(x - 3)2y = -x + 11

y = -1/2x + 5/2

y=-1/2(x)+k thru (3,4) makes k=11/2

y=-2x+b4=-2(3)+b4=-6+b4+6=b10=by=-2x+101) You want a perpendicular line, so try the negative slope...and then substitue x and y with your coordinates. Then, solve for B. (3,4) does go through the line, and does intersect.

It is easy.the eq.is modified like this..2x-y+3=0 equationof a perpendicular st.line is bx-ay+c=0.For this line it is x+2y+c=0.it passes through (3,4) so apply it.And the equation becomes 3+2(4)+c=0 so 3+8+c = 0.and so c= -11. therefore the eqution of the line is x+2y-11=0i.e.,x+2y=11.The key point for this sum is the formula.Remember equation of a st. line perpendicular to a line with equation ax+by+k=0 is bx-ay+c=0.ALL THE BEST.

how do we "guys" get these answers? When we didn't understand, we asked the teacher for help, instead of asking random people to do our homework for us.