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Old 07-24-2007   #1
gloreah
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Q- A train track rises 70m over a horizontal distance of 1.6km. What is the angle of elevation of the track to the nearest tenth of a degree? Can you show me the calculator sequence needed to solve this problem?thnx! =]
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Old 07-24-2007   #2
eyespy
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-is school NOT out yet,.?http://www.bestanswer.com
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Old 07-24-2007   #3
Grant d
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sin(x) = 0.07 / 1.6Angle X = asin (0.07 / 1.6)Calculator 0.07 / 1.6 = asin =
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Old 07-24-2007   #4
andrea y
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think of this as a right triangle. where 70 m is the segment opposite the angle x and 1600 m is the segment adjacent to x. to find x or the angle of elevation:tan (x) = 70/1600 x = tan^-1(70/1600) x = 2.51 degrees
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Old 07-24-2007   #5
hawkeye3772
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Think of it as a right trianglepposite side = 70madjacent side = 1.6km = 1600mangle = xtan x = opp/adjtan x = 70/1600x = arctan(70/1600) = 2.5 degrees
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