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07262007  #1 
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Algebra 2 help?
1. 6, 11, 16, 21 next two terms?2. 6Î£ (1/3)^K TO three decimal placesk = 33. T(1) = 2 , T(2) = = 2 Next 5 termsTn+2 = 3tn / 2tnn and n+2 is under T4.4Î£ (4k2) Terms of the series and sumK=35. In 1994 a cost of a car increase $1,942 and the cost of the car is $18,493 Write the equation. ( has to be with all the t and n stuff)6. Tn = 209n First 9 arithmic termsn is under T and 97. 5 and 3 three arithmetic means8. Four arithmetic means of 9 and 1119. 50 row theater has 20 seats in row 1 and 21 in row 2 and If each row has one more seat howmany seats in the theater10. Sum31Î£ (8k+3)k=1

07262007  #2 
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So, it's late and I'm only gonna answer #9. If there are 50 rows and the first row has 20 and the rows get larger, then each row has at least 20 seats. 50 X 20= 1,000. Now, row two has 1 additional seat than the first row, row three has 2 additional seats than the first row. So, take 1000+1+2+3....and so on until you get to +49. There's your answer.

07262007  #3 
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First Question is just finding the patternEach number in the series is 5 more than the previous number. Next two are 26 and 31.Maybe you should practice & get this concept down before proceeding to the algebraic problems.

07262007  #4 
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9. formula for an arithmetic series: (n(a1+an))/2therefore 30(20+70)/2=1350 seats

07262007  #5 
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First of all, are you not gonna try any of those problems yourself at all? Anyway ...1). Doesn't it seems like it's increasing by 5?2). 1/(3^3) + 1/(3^4) + 1/(3^5) + 1/(3^6) and it's a geometric series and r = 1/3. You should be able to solve it by simply plug in the values in geometric series equation.3). Tn+2 = 3tn / 2tnT3 = T1+2 and so, n =1.T3 = 3(t1) / 2(t1) = 3(2) / 2(2) = 3/2.By the way, are you sure the problem is Tn+2 = 3tn / 2tn? it will gives you 3/2 for every term because tn cancels each other.4). I don't know what you mean5). I don't know what you mean6). T1 = 20  9(1) = 11T2 = 20  9(2) = 2T3 = 20  9(3) = 7So, your d = 9 in the arithematic sequence equation. To find the rest of the six terms, you can use arithematic sequence formula or just continue using Tn = 20  9n.7). Arithmetic sequence formula saysan=a1+(n1)d, so plug in last term is an=3, first term a1= 5, there are three terms in between, so that makes n = 53=5+(51)d 3=5+4d8=4dd=2start with 5 and then adding 2 to 5 gives 3, and adding 2 to 3 gives 1, and adding 2 to 1 gives 1. So, your answer is 3, 1 and 1.8). Look at my answer for 7 and you should try it yourself.9). Well, you start out with 20, so your a1 = 20, your d = 1 since each row has one additional seat. So, it's gonna be,20 + 21 + 22 + ... + 69The last row is going to be 20 + 49. So, an = 69. Now you have all the term and you should be able to figure out how to use the arithematic series formula.10). 5, 13, 21, .... and looks like it's adding 8. So, your a1 = 5, and your d = 8. You can continue from now.

07262007  #6 
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1.26, 319.20 times 50 = 10001+2+3...+49 = 12251225 + 1000 = 2225

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