Range; a proof - XP Math - Forums

 XP Math - Forums Range; a proof

 10-28-2007 #1 Dreamfall Guest   Posts: n/a Range; a proof What is the proof to this function range: f(x)=Sin^2k x + Cos^2k x R=[1/2^(k-1) , 1]
 10-28-2007 #2 Temperal Guest   Posts: n/a Use $\LaTeX$. $f(x)\sin^{2k} x + \cos^{2k} x$ $R=[\left(\frac{1}{2}\right)^{k-1} , 1]$ I'll work on your problem
 10-29-2007 #3 Dreamfall Guest   Posts: n/a I think this is the right range: R=[1/(2^(k-1)) , 1]
 10-29-2007 #4 Temperal Guest   Posts: n/a But... that's the same thing. And the range seems to be incorrect. Last edited by Temperal; 10-29-2007 at 05:47 PM..
 10-29-2007 #5 Dreamfall Guest   Posts: n/a I know that's the same thing (always the shortest formula!), but the range is undoubtedly correct. I proved its right side (<=1) but the left side is still a mystery to me! Last edited by Dreamfall; 10-30-2007 at 08:07 AM..
 10-30-2007 #6 Dreamfall Guest   Posts: n/a it's fianlly done! But how can i write formulas like you?

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