12-13-2006 #1 Marcham89 Guest   Posts: n/a Can somebody please help me I have a test tomorrow. First if any one knows any good Math A sites? Plus would anyone know how to solve this problem? Could you explain it? Please. Solve the following quadratic equation. x2-3x-10=0
 12-13-2006 #2 Jack Hinkle Guest   Posts: n/a I dont know, but I boiled it down to x.x-10=3x
 12-13-2006 #3 Marcham89 Guest   Posts: n/a ............................2 I found the answer. x-3x-10=0. (The 2 is an power for x. Forget the Dots) It is (x-5)(x+2) -5,2
 12-13-2006 #4 Sillysidley   Join Date: Oct 2006 Posts: 822 the answer is x=5, or -2 __________________ .
 12-13-2006 #5 Jack Hinkle Guest   Posts: n/a Can you explain to me how you came up with that solution?
 12-13-2006 #6 Sillysidley   Join Date: Oct 2006 Posts: 822 x^2-3x-10=0 that's how it starts (this is a quadratic equation) then i factored for exampla: (x-m) (x+n) and the original is ax^2+bx+c=0 m+n must equal b, and mn must equal c. -5 and 2 add up to -3 and they multiply to get -10 therefore, it is (x-5)(x+2)=0 either x-5=0, or x+2=0 therefore x=5, or -2 now who do u think is going to win mathcounts? do u get how i did it? __________________ .

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