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Old 08-03-2007   #1
Paul W
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2x^4 - x^3y + x^2y^2 + 4xy^3 - 4y^4 divide by 2x^2 + xy - 2y^2
 
Old 08-03-2007   #2
Ian Sturdy
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x^2-xy+2y^2what you want to do, is set up the problem as follows (with bad formatting, mind you--we are doing long division, which is difficult to display on here): __x^2__-xy__+2y^2_________2x^2+xy-2y^2 | 2x^4-x^3y+x^2y^2+4xy^3-4y^4 2x^4+x^3y-2x^2y^2 ________________________ -2x^3y+3x^2y^2+4xy^3-4y^4 -2x^3y-x^2y^2+2xy^2 _____________________ 4x^2y^2+2xy^3-4y^4 4x^2y^2+2xy^3-4y^4 ________________ 0Also note, we are doing this stepwise (ie. we would add the "answer" terms one by one from left to right)
 
Old 08-03-2007   #3
joyettan
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Quotient . . . . . x^2 - xy + 2y^2...............Ans. . . . . . . . . . . .___________________________2x^2+xy-2y^2) 2x^4 - x^3y+ x^2y^2+4xy^3-4y^4. . . . . . . . . . . . .2x^4 + x^3y-2x^2y^2 â*“ â*“. . . . . . . . . . . . .----------------------------- â*“ . . . . . . . . . . . . . . . . . -2x^3y+3x^2y^2+4xy^3 â*“ . . . . . . . . . . . . . . . . .-2x^3y - x^2y^2+ 2xy^3 â*“ . . . . . . . . . . . . . . . . . ------------------------------- â*“. . . . . . . . . . . . . . . . . . . . . . . +4x^2y^2+ 2xy^3 - 4y^4. . . . . . . . . . . . . . . . . . . . . . . +4x^2y^2+ 2xy^3 - 4y^4. . . . . . . . . . . . . . . . . . . . . . . .--------------------------------Remainder. . . . . . . . . . . . . . .0...............0...............0 =================
 
 

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