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Old 12-13-2006   #1
Marcham89
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Question Can somebody please help me

I have a test tomorrow. First if any one knows any good Math A sites? Plus would anyone know how to solve this problem? Could you explain it? Please.

Solve the following quadratic equation.

x2-3x-10=0
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Old 12-13-2006   #2
Jack Hinkle
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I dont know, but I boiled it down to x.x-10=3x
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Old 12-13-2006   #3
Marcham89
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............................2
I found the answer. x-3x-10=0. (The 2 is an power for x. Forget the Dots)

It is (x-5)(x+2)

-5,2
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Old 12-13-2006   #4
Sillysidley

 
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the answer is x=5, or -2
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Old 12-13-2006   #5
Jack Hinkle
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Can you explain to me how you came up with that solution?
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Old 12-13-2006   #6
Sillysidley

 
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x^2-3x-10=0

that's how it starts (this is a quadratic equation)


then i factored

for exampla: (x-m) (x+n)

and the original is ax^2+bx+c=0
m+n must equal b, and mn must equal c.
-5 and 2 add
up to -3

and they multiply to get -10

therefore, it is (x-5)(x+2)=0

either x-5=0, or x+2=0

therefore x=5, or -2

now who do u think is going to win mathcounts?

do u get how i did it?
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