Anyone good with Algebra?? - XP Math - Forums

 XP Math - Forums Anyone good with Algebra??

 07-25-2007 #1 Miss T. Guest   Posts: n/a Anyone good with Algebra?? What is the "X" intercept of 4y-12=28x?I found the "Y" intercept... no problem. I see the 28x and I'm not sure how to get rid of the 28 and still keep both sides equal. I'm sure I'd have to divide since "28x" is multiplication... I'm just not sure where to go from there. Solve and explain, pleassssssse.
 07-25-2007 #2 Jmob26 Guest   Posts: n/a Just plug in 0 for y
 07-25-2007 #3 iluxa Guest   Posts: n/a to find y intercept, you take x = 0then 4y - 12 = 04y = 12y = 3to find x intercept, simply set y=0-12 = 28xx = -12/28x = -3/7
 07-25-2007 #4 dwinbaycity Guest   Posts: n/a x= (4y-12) /28 or (y-3)/7
 07-25-2007 #5 marissacr2004 Guest   Posts: n/a the first thing to do is find Ythen take 28 and divide it by 4the # that was 28 divide it form both sidesthen take the # that is now Y and subtract it from both sides then add 12 to both sides because it is a negativeYou should now have your answer X

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