XP Math Games Arcade

08-04-2007

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I dropped a ball from 3ft,6ft, and 12ft. For each of those positions i have to use the position function to calculate the times. My original times were .56,.61,.87. The books position function is s(t)=-16t(squared)+initial velocity(in ft)+original height. I also have to verify this algebraically. Can someone please help me?

Mr. Hui · 08-04-2007

I don't understand the problem.

$s(t)=-16{t^2}+Initial Velocity+Initial Height$

What time are you calculating for? the time it takes to hit the ground?

08-04-2007

neither do i..lol

... that is the formula my book has " the position function for a free falling object near earth's surface" unless there is a different position function that i am supposed to be using

08-04-2007

Quote:

Originally Posted by Mr. Hui

I don't understand the problem.

$s(t)=-16{t^2}+Initial Velocity+Initial Height$

What time are you calculating for? the time it takes to hit the ground?

yes the time it take to hit the ground

Mr. Hui · 08-04-2007

When you drop a book at 12 feet, the initial velocity is 0. So the position function is:

$s(t)=-16{t^2}+12=0$
$16{t^2}=12$
$t^2=0.75$
$t=\sqrt[2]0.75$
$t\approx0.87$

Conclusion: Your answer is correct.

08-06-2007

Thank, now I see what I was doing wrong. Thank you so much.

08-04-2007	#1
FEELIP Guest Posts: n/a	College Algebra Homework help -------------------------------------------------------------------------------- I dropped a ball from 3ft,6ft, and 12ft. For each of those positions i have to use the position function to calculate the times. My original times were .56,.61,.87. The books position function is s(t)=-16t(squared)+initial velocity(in ft)+original height. I also have to verify this algebraically. Can someone please help me? Last edited by FEELIP; 08-04-2007 at 11:08 AM..

08-04-2007	#2
Mr. Hui Join Date: Mar 2005 Posts: 10,609	I don't understand the problem. $s(t)=-16{t^2}+Initial Velocity+Initial Height$ What time are you calculating for? the time it takes to hit the ground? __________________ Do Math and you can do Anything! Last edited by Mr. Hui; 08-04-2007 at 01:44 PM..

08-04-2007	#5
Mr. Hui Join Date: Mar 2005 Posts: 10,609	When you drop a book at 12 feet, the initial velocity is 0. So the position function is: $s(t)=-16{t^2}+12=0$ $16{t^2}=12$ $t^2=0.75$ $t=\sqrt[2]0.75$ $t\approx0.87$ Conclusion: Your answer is correct. __________________ Do Math and you can do Anything!

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