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Old 08-04-2007   #1
Stormy Knight
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Default Coordinate geometry help?

Consider a quadrilateral ABCD in which A is (0,10). B is (2,16) and C is (8,14).(i) Show that triangle ABC is isoscelesThe point D lies on the x-axis and is such that AD=CDFind(ii) Coordinates of D(iii) Ratio of area of triangle ABC to the area of triangle ACD
Old 08-04-2007   #2
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i) you can show that 3 sides are equal.Do this for 3 times:AB=B-A=(2,6)length of AB=sqrt(4+36)=2sqrt(10)the length of BC and CA should also be 2sqrt(10)ii)AD=ACthe coordinate of D will be (0,x)use two length equation and equal them....then you can get xiii) simple division

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