Confusing - XP Math - Forums

 XP Math - Forums Confusing

 10-21-2007 #1 scoot212 Guest   Posts: n/a Confusing At a footbal game, 200 souvenirs were sold, some at $1.50 each and the rest$2.50 each. if the proceeds from the sales totaled $380, how many of each kind were sold?  10-21-2007 #2 Mr. Hui Join Date: Mar 2005 Posts: 10,609 Try guess and check or make a table. There is a method using linear programming also. Solution: (highlight to read) 120 *$1.50 + 80 *$2.50 =$380 __________________ Do Math and you can do Anything! Last edited by Mr. Hui; 10-22-2007 at 12:08 PM..
 10-21-2007 #3 hunter34 Guest   Posts: n/a Mr. Hui, you didn't follow one the problems parts. Show more: Let x be the number of $1.50 souvenirs sold, and y be the number of$2.50. So x+y=200, this means that y=200-x. Now solving the equation: $ \begin{eqnarray*} 1.50x+2.50(200-x)&=&380\\ 1.50x-2.50x+500&=&380\\ -x&=&-120\\ x&=&120 \end{eqnarray*}$ Then, you can easily find y which is 80. So the Solution to set is that there are 120 $1.50 souvenirs and 80$2.50 souvenirs. Edit:You have to fix the Hide feature so it can cover latex. Edit by Temperal: You can use [more] instead. Last edited by Temperal; 10-21-2007 at 10:32 PM..
 10-22-2007 #4 Mr. Hui     Join Date: Mar 2005 Posts: 10,609 Thanks hunter34. I completely ignored the item count constraint. I was using Excel's Solver. __________________ Do Math and you can do Anything! Last edited by Mr. Hui; 10-22-2007 at 12:10 PM..

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