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#1 |
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![]() ...at randomwillhave3men+3women From a group of 5 men and 6 women, what is the probability that a commitee formed at random will have 3 men 3 women??
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#2 |
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![]() total 6 person committees = 11*10*9*8*7*6 / 6! = 462total 3m, 3w committees = (5*4*3/6)*(6*5*4/6) = 200Probability = 200/462 = 100/231
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#3 |
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![]() maybe if one man comes and then it will be even and then have two groups of 3 men and 3 women.lol i amd sorry I sort of guessed.
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