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Old 08-05-2007   #1
always_smiling98
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B Tool Manufacturer sold a set of jigsaws to Buy Hardware. The list price was $1,950. B Tool offered a chain discount of 6/5/4. The net price of the jigsaws is:
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Old 08-05-2007   #2
Raccoon
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$585. Discount looks more like a date. I mean I read it as 6 divided by 5 divided by 4, could you clarify so I can edit accordingly.
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Old 08-05-2007   #3
Some Guy in IT
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Apply a 6 percent discount, get the result, apply a 5 percent discount to that, get the result, and then apply a 4 percent discount to that to get your answer. The answer is $1671.70 ($1950 * .94 * .95 * .96 = $1671.70)
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Old 08-05-2007   #4
Craig M
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The list price = $1950Let us define some notations to make the calculations easier.P refers to the Principal Amount.DP1 refers to the Discounted price after the First discount(d1).DP2 refers to the Discounted price after the Second discount(d2).DP3 refers to the Discounted price after the Third discount(d3).DP1 = P – (d1 x P)DP2 = P – (d1 x P) – d2(P – (d1 x P)) = DP1 – d2(DP1)DP3 = DP2 – d3(DP2)DP4 = DP3 – d4(DP3)DP1 = 1950 – (6/100)(1950) = 1950 – (0.06 x 1950) = 1950 – 117 DP1 = $1833DP2 = 1833 – (5/100)(1833) = 1833 – (0.05 x 1833) = 1833 – 91.65 DP2 = $1741.35DP3 = 1741.35 – (4/100)(1741.35) = 1741.35 – (0.04 x 1741.35) = 1741.35 – 69.65 DP3 = $1671.70Since, B Tool has offered only 3 successive discounts, the process should be stopped after the third discount.So, the net price of the jigsaws after 3 successive discounts is $1671.70.Require additional practice in arithmetic/algebra/geometry? Visit http://www.icoachmath.com/
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