08-01-2007 #1 sweetlady Guest   Posts: n/a math solutions algebra please help I need this in 3 hours? 1. Rewrite as a single logarithm without negative exponents: log x ^-10 +log 2x^2 - 3 log (2x)^22. If log a 2 =0.613 and log a 5 = 0.128, computea.) log a 50=b.) log a 64=c.) log a 2.5=3.Find the inverse function f(x)= 2x^2-5x / x in other words:2x^2 -5x_____ = x
 08-01-2007 #2 noy k Guest   Posts: n/a 2a) log a 50 = log a 5 X log a 5 X log a2 = 0.128 X 0.128 X 0.613

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