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Old 08-01-2007   #1
Blue L
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Default I need help for algebra !!! Please give me answers?

I need answers for these questions and I really need help!! Please helpay-b=c solve for ya(y+1)=b solve for yax+b=cx solve for xay+z=am-ny solve for yThe digits below are in a special order. What order is it? 0,2,3,6,7,1,9,4,5,8
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Old 08-01-2007   #2
earthdrivenforce
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PROBLEM 1:ay - b = cfirst add "b" to both sides... like this...(ay - b) + b = c + bnow combine "like" terms... to get...ay = c + bnow divide both sides by "a"(ay)/a = (c + b) / a.... and the "a's" cancel out on the left side...y = (c + b) / aPROBLEM 2:a(y+1)=b solve for ya * y + a * 1 = bay + a = bnow SUBTRACT "a" from both sides... like this...(ay + a) - a = b - acombine "like" terms... to get...ay = b - anow divide both sides by "a"(ay)/a = (b - a) / a.... and the "a's" cancel out on the left side...y = (b - a) / ay = b/a - a/ay = b/a - 1PROBLEM 3:ax+b=cx solve for xyou want to move all the x's to either the left or right side...I'm going to move them to the left side...ax + b = cxsubtract "cx" from both sides... like this...(ax + b) - cx = cx - cxcombine "like" terms to get...ax + b - cx = 0now subtract "b" from both sides... like this...(ax + b - cx) - b = 0 - bcombine "like" terms... to get...ax - cx = -bnow factor out x on the left side.... like this...x(a - c) = -bnow divide both sides by "(a-c)"... like this...x(a - c) / (a-c) = -b / (a - c)the (a-c)'s on the left cancel each other out...and you are left with...x = - b / (a - c)PROBLEM 4:ay + z = am - nyyou want to get all the y's on one side... I will put them all on the left side...ay + z = am - nyadd "ny" to both sides...(ay + z) + ny = (am - ny) + nycombine like terms...ay + z + ny = amsubtract "z" from both sides...(ay + z + ny) - z = am - zcombine like terms...ay + ny = am - zfactor "y" on left side...y (a + n) = am - zdivide both sides by (a+n)y = (am - z) / (a + n)PROBLEM 5:0, 2, 3, 6, 7, 1, 9, 4, 5, 8...They are 1-digit numbers in reversed alphabetical orderZero, Two, Three, Six, Seven, One, Nine, Four, Five, Eight...
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Old 08-01-2007   #3
nowask_me
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the process of the guy above is right the answers1 y=(c+b)/a2 y=b/a -13 b/(c-a)=x4 y=(am-z)/(a+n)5 sorry dont remember that
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Old 08-01-2007   #4
joky
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ay-b=cay=c+by=(c+b)/aa(y+1)=by-1=b/ay=(b/a)-1ax+b=cxax-cx=-bx(a-c)=-bx=-b/(a-c)ay+z=am-nyay+ny=am-zy(a+n)=am-zy=(am-z)/(a+n)i hope can help u larr...another one i also donno..
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