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Old 08-01-2007   #1
Strawberry
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Default geometry proofs parallelagrams PLEASE HELP!?

Write a two-column proof to show RSTW is a parallelogram using the method that states that if one pair of opposite sides is both parallel and congruent then the quadrilateral is a parallelogram.RSTW has dignoals that bisect at point V Given:
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Old 08-01-2007   #2
davec996
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It's been a long time, and we probably speak different (mathematical) languages -- so I'll refer to the document listed as the source -- you'll have to translate it into what you know. OK -- lets go. (What's a 2 column proof?)RSTW is a quadrilateral. -- given.First lets prove that RS is parallel with WT. (= means congruent)âˆ*RSW = âˆ*TWS -- givenâˆ*RSW = âˆ*TWS are alternate angles made by the intersection of line WS with lines RS and WT - givenRS is parallel with WT -- source-proposition 27.now show RS = WTRV=VT - given WS & RT are bisected at VWV=VS - given WS & RT are bisected at Vâˆ*RVS = âˆ*WVT -- source-Prop 15âˆ*RVS = âˆ*WVT -- side-angle-sideRS = WT -- congruent trianglesRSTW is a parallelogram -- If one pair of opposite sides is both parallel and congruent then the quadrilateral is a parallelogram -QED































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