math

2x+5/5=3x+1/2+-x+7/2

2x+5/5=3x+1/2+-x+7/2

is this how it should look? because i can only figure from what you typed
(2x+5)/5 = (3x+1)/2 + (-x+7)/2
if it does then combine the right side together since both expressions have common denominator of 2. then you should have

(2x+5)/5 = (3x+1+-x+7)/2
(2x+5)/5 = (2x+8)/2

Now you can cross multiply because you have a fraction equal to a fraction

(2x+5) *times* 2 = (2x+8) *times* 5
4x+10 = 10x+40

now bring all variable (x) to one side and constant to the other. I want to bring 4x to the right and 40 to the left. I would have:

4x + 10 = 10x + 40
-4x -40 =-4x -40
-30 = 6x

divide 6 to both sides

-30=6x
6 = 6

you should get:
x=-5

Check your work by plug -5 back into the original equation to see if it is correct.

Hope that helps

good explation fav dog u are really good in math why dont you challenge me

challenge you at what? I am new here so tell me what's going on.

you go to my pro file then you go to my last post and then you click on my last post i did then on the bottom its going to say challenge galal95





thats it

It's pretty much the same as the first reponse's:
(2x+5)/5 = (3x + 1)/2 + (-x + 7)/2
=4x+10 = 15x+5-5x+35 (by multiplying both sides by 10)
= 4x + 10 = 10x + 40 (simplification)
=-6x = 30
x=-5


DONE!!!