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 07-26-2007 #1 FunnyGirl007 Guest   Posts: n/a Algebra 2 help? 1. 6, 11, 16, 21 next two terms?2. 6Î£ (1/3)^K TO three decimal placesk = 33. T(1) = -2 , T(2) = = -2 Next 5 termsTn+2 = 3tn / 2tnn and n+2 is under T4.4Î£ (4k-2) Terms of the series and sumK=35. In 1994 a cost of a car increase \$1,942 and the cost of the car is \$18,493 Write the equation. ( has to be with all the t and n stuff)6. Tn = 20-9n First 9 arithmic termsn is under T and 97. 5 and -3 three arithmetic means8. Four arithmetic means of -9 and 1119. 50 row theater has 20 seats in row 1 and 21 in row 2 and If each row has one more seat how-many seats in the theater10. Sum31Î£ (-8k+3)k=1
 07-26-2007 #2 kankles919 Guest   Posts: n/a So, it's late and I'm only gonna answer #9. If there are 50 rows and the first row has 20 and the rows get larger, then each row has at least 20 seats. 50 X 20= 1,000. Now, row two has 1 additional seat than the first row, row three has 2 additional seats than the first row. So, take 1000+1+2+3....and so on until you get to +49. There's your answer.
 07-26-2007 #3 bedbye Guest   Posts: n/a First Question is just finding the patternEach number in the series is 5 more than the previous number. Next two are 26 and 31.Maybe you should practice & get this concept down before proceeding to the algebraic problems.
 07-26-2007 #4 CwCc Guest   Posts: n/a 9. formula for an arithmetic series: (n(a1+an))/2therefore 30(20+70)/2=1350 seats
 07-26-2007 #5 Lain Lain Guest   Posts: n/a First of all, are you not gonna try any of those problems yourself at all? Anyway ...1). Doesn't it seems like it's increasing by 5?2). 1/(3^3) + 1/(3^4) + 1/(3^5) + 1/(3^6) and it's a geometric series and r = 1/3. You should be able to solve it by simply plug in the values in geometric series equation.3). Tn+2 = 3tn / 2tnT3 = T1+2 and so, n =1.T3 = 3(t1) / 2(t1) = 3(-2) / 2(-2) = 3/2.By the way, are you sure the problem is Tn+2 = 3tn / 2tn? it will gives you 3/2 for every term because tn cancels each other.4). I don't know what you mean5). I don't know what you mean6). T1 = 20 - 9(1) = 11T2 = 20 - 9(2) = 2T3 = 20 - 9(3) = -7So, your d = -9 in the arithematic sequence equation. To find the rest of the six terms, you can use arithematic sequence formula or just continue using Tn = 20 - 9n.7). Arithmetic sequence formula saysan=a1+(n-1)d, so plug in last term is an=-3, first term a1= 5, there are three terms in between, so that makes n = 5-3=5+(5-1)d -3=5+4d-8=4dd=-2start with 5 and then adding -2 to 5 gives 3, and adding -2 to 3 gives 1, and adding -2 to 1 gives -1. So, your answer is 3, 1 and -1.8). Look at my answer for 7 and you should try it yourself.9). Well, you start out with 20, so your a1 = 20, your d = 1 since each row has one additional seat. So, it's gonna be,20 + 21 + 22 + ... + 69The last row is going to be 20 + 49. So, an = 69. Now you have all the term and you should be able to figure out how to use the arithematic series formula.10). -5, -13, -21, .... and looks like it's adding -8. So, your a1 = -5, and your d = -8. You can continue from now.
 07-26-2007 #6 mcbrocks Guest   Posts: n/a 1.26, 319.20 times 50 = 10001+2+3...+49 = 12251225 + 1000 = 2225

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