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07252007  #1 
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could someone help me with this assignment in Algebra?
1) (x + 2y + 2z)sqare2) (2x + 3y  4z + 3w)square3) (xsquare  2x + 3)square4) (2x + 3yz + w)sqare5) (x + y  3z)square6) (x + y)to the 4thplease do include your solutions, I would really appreciate the helps. T_T

07252007  #2 
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It's the same process for all of them... just expand and simplify.(x+2y+2z)^2= x^2 + 2xy + 2xz + 2xy + 4y^2 + 4yz + 2xz + 4yz + 4z^2= 4y^2 + 4z^2 + x^2 + 4xy + 4xz + 8yz...You can do the rest =), good luck.

07252007  #3 
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Multiply each term in the expression by the whole expression and add like terms. For examplex + 2y + 2z)^2 = (x + 2y + 2z)*(x + 2y + 2z)Multiplying the first term (x) by the full expression (x + 2y + 2z) getx^2 + 2xy + 2xz (a)Now do the same with the second term (2y)2xy + 4*y^2 + 4*y*z (b)and finally the last term (2z)2xz + 4zy + 4z^2 (c)Then add them all [(a) + (b) + (c)] together and collect like terms.

07252007  #4 
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1) (x+2y+2z)(x+2y+2z) (x^2+2xy+2xz)+(2xy+4y^2+4zy)+(2xz+4zy+4z^2) x^2+4xy+4xz+4y^2+8zy+4z^2

07252007  #5 
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(x + 2y + 2z)^2 = x^2 + 4y^2 + 4z^2 + 4xy + 4xz + 8yz(2x + 3y  4z + 3w)^2 = 4x^2 + 9y^2 + 16z^2 + 9w^2 + 12xy  16xz + 12xw  24yz +18yx  24zw(x^2  2x + 3)^2 = x^4 + 4x^2 + 9  4x^3 + 6x^2  12x = x^4  4x^3 + 10x^2  12x + 9(2x + 3yz + w)^2 = 4x^2 + 9y^2z^2 + w^2 + 12xyz + 4xw + 6yzw(x + y  3z)^2 = x^2 + y^2 + 9z^2 + 2xy 6xz  6yz(x + y)^4 = x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4

07252007  #6 
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Hhm perhaps you need the definition of a square, a square is an equation to the power of 2. 2 squared is 4,the square root of 4 is 2 (2*2=4). Given above the answer to number 1 is (x + 2y + 2z)*(x + 2y + 2z) =yum alegbra!!!!!!

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