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Old 07-16-2007   #1
Berry A
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Default please help me with this math question?

Write an equation of a line that is perpendicular to y = 2x + 3 and passes through (3,4).how do you guys get these answers?...do you solve them by yourselfs or do u use a website?
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Old 07-16-2007   #2
sahsjing
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y - 4 = (-1/2)(x-3), in point-slope form-------------Reason: (-1/2)(2) = -1. If one slope is 2, then the other one must be -1/2 if the two lines are perpendicular to each other.
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Old 07-16-2007   #3
T.O.
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Y=5x+3?
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Old 07-16-2007   #4
MsMath
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y = -(1/2)x + 11/2
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Old 07-16-2007   #5
jed
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y = 2x + 3so the slope of this line is m = 2the slope of line perpendicular this line is m = -1/2if it passes through (3,4) therefore(y - y1) = m (x - x1)(y - 4) = -(1/2)(x - 3)2y = -x + 11
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Old 07-16-2007   #6
xjmox14x
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y = -1/2x + 5/2
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Old 07-16-2007   #7
rwbblb46
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y=-1/2(x)+k thru (3,4) makes k=11/2
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Old 07-16-2007   #8
Michelle D
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y=-2x+b4=-2(3)+b4=-6+b4+6=b10=by=-2x+101) You want a perpendicular line, so try the negative slope...and then substitue x and y with your coordinates. Then, solve for B. (3,4) does go through the line, and does intersect.
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Old 07-16-2007   #9
Aishu
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It is easy.the eq.is modified like this..2x-y+3=0 equationof a perpendicular st.line is bx-ay+c=0.For this line it is x+2y+c=0.it passes through (3,4) so apply it.And the equation becomes 3+2(4)+c=0 so 3+8+c = 0.and so c= -11. therefore the eqution of the line is x+2y-11=0i.e.,x+2y=11.The key point for this sum is the formula.Remember equation of a st. line perpendicular to a line with equation ax+by+k=0 is bx-ay+c=0.ALL THE BEST.
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Old 07-16-2007   #10
b p
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how do we "guys" get these answers? When we didn't understand, we asked the teacher for help, instead of asking random people to do our homework for us.
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