Sign Up FREE!  Sign In  Classroom Setup  Common Core Alignment  


Thread Tools  Display Modes 
07172007  #1 
Guest
Posts: n/a

If four fair coins are tossed, find the probability of getting exactly no heads?
If four fair coins are tossed, find the probability of getting exactly no heads?

07172007  #2 
Guest
Posts: n/a

1 in 16.Here are the probs for all combinations:You can use binomial coefficients for 4th order to find this:1, 4, 6, 4, 1, the sum is 16. So...1:16 for all tails4:16 for 3 tails, 1 heads6:16 for 2 tails, 2 heads4:16 for 1 tails, 3 heads1:16 for all heads

07172007  #3 
Guest
Posts: n/a

its 1/16, the same as all heads

07172007  #4 
Guest
Posts: n/a

It is the same as getting all Tails.

07172007  #5 
Guest
Posts: n/a

Probability of heads 1/2 2/4 are heads or 1/24 different coinsmultiply1/2x1/2x1/4=1/16

07172007  #6 
Guest
Posts: n/a

chance of not getting heads on 1 coin is .5so not getting heads on 4 coins thrown at the same time is.5 * .5 * .5 * .5 = .0625 or 6.25%

07172007  #7 
Guest
Posts: n/a

1st coin tossed probability of getting tails is 1 in 2.2nd coin tossed probability of getting tails is 1 in 2.3rd coin tossed probability of getting tails is 1 in 2.4th coin tossed probability of getting tails is 1 in 2.2 x 2 x 2 x 2 = 16So the probability of getting heads every time is 1 in 16.

07172007  #8 
Guest
Posts: n/a

1 whole=four tailsif you flip the 4 coins, and they all turn out to be tails, there is no possible way that there can be heads, so the four coins which equals 4 tails=1 whole.need more help? Im always here!Hannah

07172007  #9 
Guest
Posts: n/a

1:5764x3x2x1x4x3x2x1=576OR1:48(4x3x2x1)+(4x3x2x1)= 48I seem to remember the equation going something like that for probability. Although it has been some time since I learned it.

Thread Tools  
Display Modes  

