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Old 07-17-2007   #1
whatif2727
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Default If four fair coins are tossed, find the probability of getting exactly no heads?

If four fair coins are tossed, find the probability of getting exactly no heads?
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Old 07-17-2007   #2
Jerry P
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1 in 16.Here are the probs for all combinations:You can use binomial coefficients for 4th order to find this:1, 4, 6, 4, 1, the sum is 16. So...1:16 for all tails4:16 for 3 tails, 1 heads6:16 for 2 tails, 2 heads4:16 for 1 tails, 3 heads1:16 for all heads
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Old 07-17-2007   #3
dr schmitty
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its 1/16, the same as all heads
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Old 07-17-2007   #4
Doug
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It is the same as getting all Tails.
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Old 07-17-2007   #5
Irina MD
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Probability of heads 1/2 2/4 are heads or 1/24 different coinsmultiply1/2x1/2x1/4=1/16
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Old 07-17-2007   #6
haggismoffat
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chance of not getting heads on 1 coin is .5so not getting heads on 4 coins thrown at the same time is.5 * .5 * .5 * .5 = .0625 or 6.25%
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Old 07-17-2007   #7
karate09
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1st coin tossed probability of getting tails is 1 in 2.2nd coin tossed probability of getting tails is 1 in 2.3rd coin tossed probability of getting tails is 1 in 2.4th coin tossed probability of getting tails is 1 in 2.2 x 2 x 2 x 2 = 16So the probability of getting heads every time is 1 in 16.
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Old 07-17-2007   #8
clemintineshimmer
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1 whole=four tailsif you flip the 4 coins, and they all turn out to be tails, there is no possible way that there can be heads, so the four coins which equals 4 tails=1 whole.need more help? Im always here!-Hannah
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Old 07-17-2007   #9
Stevo
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1:5764x3x2x1x4x3x2x1=576OR1:48(4x3x2x1)+(4x3x2x1)= 48I seem to remember the equation going something like that for probability. Although it has been some time since I learned it.
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