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Old 10-21-2007   #1
scoot212
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At a footbal game, 200 souvenirs were sold, some at $1.50 each and the rest $2.50 each. if the proceeds from the sales totaled $380, how many of each kind were sold?
 
Old 10-21-2007   #2
Mr. Hui


 
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Try guess and check or make a table. There is a method using linear programming also.

Solution: (highlight to read)
120 * $1.50 + 80 *$2.50 = $380
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Last edited by Mr. Hui; 10-22-2007 at 12:08 PM..
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Old 10-21-2007   #3
hunter34
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Mr. Hui, you didn't follow one the problems parts.
Show more:

Let x be the number of $1.50 souvenirs sold, and y be the number of $2.50. So x+y=200, this means that y=200-x. Now solving the equation:

Then, you can easily find y which is 80. So the Solution to set is that there are 120 $1.50 souvenirs and 80 $2.50 souvenirs.


Edit:You have to fix the Hide feature so it can cover latex.

Edit by Temperal: You can use [more] instead.

Last edited by Temperal; 10-21-2007 at 10:32 PM..
 
Old 10-22-2007   #4
Mr. Hui


 
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Thanks hunter34. I completely ignored the item count constraint.

I was using Excel's Solver.
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Last edited by Mr. Hui; 10-22-2007 at 12:10 PM..
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